Uva 100 - The 3n+1

問題網址
有幾點要考慮：

1. 讀取的行數不是單行
2. 每行的兩個數值，不一定是前小後大

#include <stdio.h>
int cycleLength(int number);
int main()
{
  int i, j, input1, input2;
 
  while( scanf("%d %d",&input1, &input2) != EOF ){
  
      //檢查與調整前後大小
      if(input1 < input2){
          i = input1;
          j = input2;
      }else{
          i = input2;
          j = input1;
      }
  
  
      int maxCycleLength = 0;
      long int x;
      
      for ( x = i; x <=j ; x++){
          int c = cycleLength(x) ;
          if (c > maxCycleLength){
              maxCycleLength = c ;
          }
      }
      printf("%d %d %d\n",input1,input2, maxCycleLength );
 }
 
 
 return 0;
}

int cycleLength(int number)
{
    int c = 1;
    while(number!=1){
        if(number%2==1){
            number = 3*number +1;
            c++;
        }else{
            number = number/2;
            c++;
        }
    }
 return c;
}

解了此題，但是速度太慢（run time:0.612），要嘗試用別種方法